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Re: integrate problem
*To*: mathgroup at smc.vnet.net
*Subject*: [mg98872] Re: [mg98837] integrate problem
*From*: Andrzej Kozlowski <akoz at mimuw.edu.pl>
*Date*: Mon, 20 Apr 2009 19:11:46 -0400 (EDT)
*References*: <200904200939.FAA12325@smc.vnet.net>
On 20 Apr 2009, at 18:39, sean_incali at yahoo.com wrote:
> I'm having some issues understanding this... Following works as
> expected.
>
> s is the variable in time. a is a parameter.
>
> Integrate[1/(s + a), s]
>
> gives Log[a + s]
>
> But the following gives the integral itself.
>
> Integrate[1/(s[t] + a), t]
>
> If the function that needs to be integrated w.r.t time is 1/(s[t] +
> a), how do I accomplish that?
You can't accomplish that unless you give Mathematica an explicit
expression for s[t] (and you will have to be lucky then too). How
could you possible expect this to work in general? If this did, you
could integrate practically any function f[t] by using a suitable
s[t]. This has nothing to do with Mathematica, its just basic
mathematics.
> It seems like if integrate it wrt to s
> [t] it will work.
>
> Integrate[1/(s[t] + a), s[t]]
>
>
> But does that sound about right?
Right? In what sense "right"? It's a completely different thing from
your first case. Here you might as well write t (or s) instead of s[t]
as it has nothing whatever to do with s[t].
Note that this also gives an answer:
Integrate[s'[t]/(a + s[t]), t]
Log[a+s[t] ]
but this also has nothing to do with your original integral...
Andrzej Kozlowski
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