Re: HoldForm in defined function doesn't seem to work

*To*: mathgroup at smc.vnet.net*Subject*: [mg99242] Re: HoldForm in defined function doesn't seem to work*From*: dh <dh at metrohm.com>*Date*: Thu, 30 Apr 2009 06:26:18 -0400 (EDT)*References*: <gt9aki$q22$1@smc.vnet.net>

Hi joel, by default, function arguments are evaluated before beeing fed the the function. Therefore, f already gets the evaluated result. To change this you must e,g, give f the attribute: HoldAll or HoldFirst.: =================== SetAttributes[f, HoldAll]; f[x_] = HoldForm[x]; HoldForm[123 456 789] f[123 456 789] ==================== Daniel joel.aufgang at gmail.com wrote: > I'm struggling to understand why this doesn't work: > > > f[x_] = HoldForm[x]; > HoldForm[123 456 789] (* returns "123 x 456 x 789" *) > f[123 456 789] (* returns"44253432" *) > > I don't understand why the two results are different. Is there a > special trick I need to do to be able to define f so that the HoldForm > works? > > I'm using this to help visualize the way a notebook represents typed > expressions, so I'm trying to do something like this: > > BoxTree[expr_] := TreeForm[ToBoxes[HoldForm[expr]][[1]]]; > a b c d e // BoxTree > 123 456 789 // BoxTree (* want this to show as a RowBox like the > previous example *) > > > Any help would be greatly appreciated. Thanks. >