Dynamically create array and display data graphically
- To: mathgroup at smc.vnet.net
- Subject: [mg102497] Dynamically create array and display data graphically
- From: Tuhina Singh <tuhina.singh at rmilindia.com>
- Date: Tue, 11 Aug 2009 04:05:23 -0400 (EDT)
Hi, Please bear with me if you find this a simplistic problem. Just learning to find my way around mathematica. b = Import["C:\Practice\example1.xls",{"Data",1}] (* Import file - several columns of data with first row having headers *) Manipulate[Manipulate[DateListPLot[{Take[b,{2,p}][[All,a]]}, {{2009,7,8},Automatic,"Day"},Joined->True],{p,2,35,1}],{a,2,5,1}] In this code, I am able to specify the column I want displayed using the outer manipulate fn, and the inner manipulate function changes the number of rows of data displayed. Now I want to change this function so that the outer manipulate fn specifies the "number of columns" to be displayed. So that if a = 3, I see three series in the graph with "p" rows of data shown in the graph. I tried the following with no success: Manipulate[{Do[col[[x]]= DateListPLot[{Take[b,{2,35}][[All,x]]}, {{2009,7,8},Automatic,"Day"},Joined->True, DisplayFunction->Identity],{x,2,a,1}], Do[Show[col[[x]], DisplayFunction->$DisplayFunction],{x,2,a,1}]}, ,{a,2,5,1}] Was basically trying to loop "a" times to dynamically create an array of dimension [a, 35] and then display them all together using Show function. But value of "a" doesn't get passed on and I believe use of the Do loop is also wrong here. Thanks for ur help. Regards, Tuhina ________________________________ Tuhina Singh Siddhesh Capital Market Services Pvt Ltd. 122, Maker Chambers III, 12th Floor Nariman POint Mumbai - 400 021 Tel (D): 91-22-4057 0322 (B): 91-22-4057 0300 Fax: 91-22-2285 2912
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