Services & ResourcesWolfram ForumsMathGroup Archive

[Date Index] [Thread Index] [Author Index]

A Question about Combinatorica

• To: mathgroup at smc.vnet.net
• Subject: [mg102627] A Question about Combinatorica
• From: Marwa Abd El-Wahaab <m.a.elwahaab at gmail.com>
• Date: Mon, 17 Aug 2009 04:04:09 -0400 (EDT)

Dear Sir,
I have a question about having five letters like {A, B, C, D, E}. In order
to get all possibilities, we have 5! possible cases like ABCDE,
EABCD,.......etc

The number of these possibilities are 120. How and why this number becomes
 60 by dividing by 2 ?

What are 60 possibilities & how extract them from 120?

I used this function to get 120:

MinimumChangePermutations[{A,B,C,D,E}]

 What should I do after this to get 60?

Thanks too much

I really need your help

*Marwa Ali Abd El Wahaab*
*Teaching Assistant*
Faculty of Engineering
Mansoura University

• Follow-Ups:
  • Re: A Question about Combinatorica
    • From: Murray Eisenberg <murray@math.umass.edu>
  • Re: A Question about Combinatorica
    • From: Andrzej Kozlowski <akoz@mimuw.edu.pl>