Re: problem with EvenQ
- To: mathgroup at smc.vnet.net
- Subject: [mg105952] Re: [mg105923] problem with EvenQ
- From: Bob Hanlon <hanlonr at cox.net>
- Date: Sun, 27 Dec 2009 02:27:12 -0500 (EST)
- Reply-to: hanlonr at cox.net
y /. FindInstance[
y*2 < 100 && y > 0 && 2*Round[y/2] == y,
y, Integers, 5] // Sort
{6,10,16,42,44}
y /. FindInstance[
y*2 < 100 && y > 0 && 2*IntegerPart[y/2] == y,
y, Integers, 5] // Sort
{6,10,16,42,44}
y /. FindInstance[
{z == y/2, y*2 < 100, y > 0, Element[z, Integers]},
{y, z}, Integers, 5] // Sort
{6,10,16,42,44}
Bob Hanlon
---- dvholten <info at dvholten.de> wrote:
=============
Hi folks,
i puzzled all afternoon, but couldnt get this one solved:
what is the proper way of using EvenQ[] within FindInstance[] ?
I cant use it like
FindInstance[ y*2 < 100 && EvenQ[y], {y}, Integers ]
or even
FindInstance[ EvenQ[y], {y}, Integers ]
Actually, the expression used in FindInstance is much more complex,
but i condensed the problem to be EvenQ[] - i expect some kind of
special notation to help here.
thanks
dvh