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Re: Re: Functions inside modules with external definitions
*To*: mathgroup at smc.vnet.net
*Subject*: [mg96568] Re: [mg96505] Re: Functions inside modules with external definitions
*From*: "E. Martin-Serrano" <eMartinSerrano at telefonica.net>
*Date*: Mon, 16 Feb 2009 07:00:27 -0500 (EST)
*References*: <gn5ugm$h02$1@smc.vnet.net> <200902150819.DAA07828@smc.vnet.net>
Jens,
I use Module[] because the definition of f[] is inside a Module with a lot
of dynamic stuff (say 200 lines of code); and f[] (and other function
definitions, local to the module, are the root of all the dynamic treatment.
I never thought of Block as a construct or "container" for dynamic programs.
But maybe I was wrong.
Well, I tried many other approaches before posting but I did want to mess up
the example with other details.
I will review the other answers I have had, see what happens, and prepare a
full feedback if necessary. But, please, I would appreciate your remarks to
this as your solution works as needed. (Although, inside Block[]).
Regards
Emilio.
-----Original Message-----
From: Jens-Peer Kuska [mailto:kuska at informatik.uni-leipzig.de]
Sent: Sunday, February 15, 2009 9:20 AM
To: mathgroup at smc.vnet.net
Subject: [mg96568] [mg96505] Re: Functions inside modules with external definitions
Hi,
and my question is "Why do you use Module[] ?"
expression = a x^c + b y^(1 - c);
mx = Block[{f, expression = expression},
f[x_: x, y_: y][a_ : a, b_: b, c_: c] := Evaluate@expression;
f[k1, k2][.2, .3, .4]
]
work as expected.
Regards
Jens
E. Martin-Serrano wrote:
> Hi,
>
>
>
> Please review the following and see weather my question has and deserves
an
> answer. It is a about defining functions local to modules but using
external
> definitions of the right hand side of the local function and passed as
> parameters to the module.
>
>
>
>
>
> expression = a x ^c + b y ^(1-c) (* or whatever expression *)
>
>
>
> Clear[f];
>
>
>
> f[x_: x,y_: y][a_: a,b_: b,c_: c]:=Evaluate@expression
>
>
>
> ?f
>
> f[k1,k2][.2,.3,.4]
>
>
>
> (* Functions inside modules where the RHS of the function has been
assigned
> to a variable *)
>
> (* first form works as I expected, but uses an extrenal definition for a
> local function (the name is local) *)
>
>
>
> m1=
>
> Module[{f},
>
> f[x_: x,y_: y][a_ :a,b_: b,c_: c]:=Evaluate@expression;
>
> f[k1,k2][.2,.3,.4]
>
> ]
>
>
>
> (* second form. I expected it worked as the one above but it does not;
the
> expression formed outside is assigned to a local variable with the same
name
> *)
>
>
>
> m2 =
>
> Module[{f, expression = expression},
>
> f[x_: x, y_: y][a_ :a,b_: b,c_: c]:=Evaluate@expression;
>
> f[k1,k2][.2,.3,.4]
>
> ]
>
>
>
> (* third form. I expected it worked as the first one above but it does
not;
> the expression is assigned directly to a local variable *)
>
>
>
> m3 =
>
> Module[{f,expression = a x ^c + b y ^(1-c)},
>
> f[x_: x,y_: y][a_ :a,b_: b,c_: c]:=Evaluate@expression;
>
> f[k1,k2][.2,.3,.4]
>
> ]
>
>
>
> (* fourth form. I expected it worked as the first one above but it does
not;
> the expression is assigned within the body of the module o a local
variable
> *)
>
>
>
> m4 =
>
> Module[{f,expr},
>
> expr =expression;
>
> f[x_: x,y_: y][a_ :a,b_: b,c_: c]:=Evaluate@expr;
>
> f[k1,k2][.2,.3,.4]
>
> ]
>
>
>
> (* My question is how to construct a function inside a module in manner
> similar to the following *)
>
>
>
> expression = a x ^c + b y ^(1-c);
>
> mx =
>
> Module[{f,expression = expression},
>
> f[x_: x,y_: y][a_ :a,b_: b,c_: c]:=Evaluate@expression;
>
> f[k1,k2][.2,.3,.4]
>
> ]
>
>
>
> (* and working as the following works *)
>
>
>
> m1=
>
> Module[{f},
>
> f[x_: x,y_: y][a_ :a,b_: b,c_: c]:=Evaluate@expression;
>
> f[k1,k2][.2,.3,.4]
>
> ]
>
>
>
> Many thanks
>
>
>
>
>
> E. martin-Serrano
>
>
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