Re: question related to (-1)^(1/3)
- To: mathgroup at smc.vnet.net
- Subject: [mg96732] Re: [mg96711] question related to (-1)^(1/3)
- From: Murray Eisenberg <murray at math.umass.edu>
- Date: Mon, 23 Feb 2009 05:01:49 -0500 (EST)
- Organization: Mathematics & Statistics, Univ. of Mass./Amherst
- References: <200902220533.AAA12584@smc.vnet.net>
- Reply-to: murray at math.umass.edu
No, because (-1)^(1/3) is NOT -1. Rather, it is the principal cube-root of -1. =D2=BB=D2=B6=D6=AA=C7=EF wrote: > I have tried expression: > RecurrenceTable[{x[n + 1] == -x[n]^(1/3), x[0] == 1}, > x, {n, 1, 200}] // N > > Mathematica produce > {-1., -0.5 - 0.866025 I, -0.766044 + 0.642788 I, -0.686242 - > 0.727374 I, -0.71393 + 0.700217 I, -0.704818 - 0.709389 I, > ... > > But it should be {1, -1, 1, -1, ... } > > If you try (-1)^(1/3) > > In[10]:= (-1)^(1/3) > > Out[10]= (-1)^(1/3) > > In[11]:= % // N > > Out[11]= 0.5 + 0.866025 I > > > -- Murray Eisenberg murray at math.umass.edu Mathematics & Statistics Dept. Lederle Graduate Research Tower phone 413 549-1020 (H) University of Massachusetts 413 545-2859 (W) 710 North Pleasant Street fax 413 545-1801 Amherst, MA 01003-9305
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- question related to (-1)^(1/3)
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- question related to (-1)^(1/3)