Re: MeijerG

*To*: mathgroup at smc.vnet.net*Subject*: [mg95175] Re: MeijerG*From*: dh <dh at metrohm.com>*Date*: Thu, 8 Jan 2009 06:43:23 -0500 (EST)*References*: <gk3fba$dt9$1@smc.vnet.net>

Hi Dimitris, simply try it out numerically. E.g. setting c->1 you can use NLimit. This is in agreement with "Limit". Therefore, it is certainly not "Infinity". Or you could numerically calculate the value for different x and c. This also agrees well with the solution from Limit. Daniel dimitris wrote: > Can I trust the following result? > > In[29]:= Limit[-Log[x^2] - > Sqrt[Pi]*MeijerG[{{0}, {}}, {{0, 0}, {1/2}}, x^2/(4*c)], x -> 0] > (*c>0*) > > Out[29]= 2*EulerGamma + Log[1/c] > > Another well known CAS gave > >> limit(-ln(x^2)-sqrt(Pi)*MeijerG([[0], []],[[0, 0], [1/2]],1/4*x^2/c),x = 0); > >> infinity > > > Regards > Dimitris >