Re: Re: ListCurvePathPlot

*To*: mathgroup at smc.vnet.net*Subject*: [mg95996] Re: [mg95942] Re: ListCurvePathPlot*From*: DrMajorBob <btreat1 at austin.rr.com>*Date*: Sat, 31 Jan 2009 06:44:58 -0500 (EST)*References*: <gls253$hq3$1@smc.vnet.net> <200901301045.FAA06534@smc.vnet.net>*Reply-to*: drmajorbob at longhorns.com

This gives ONE path on some draws, two, three, or four on others, et cetera: data = Table[ RandomReal[{.8, 1.2}] {Cos[t], Sin[t]}, {t, 0, 2 \[Pi] - 2 \[Pi]/6, 2 \[Pi]/32}]; ListCurvePathPlot[data, InterpolationOrder -> 2, Axes -> False, InterpolationOrder -> 16] Sometimes if there's one path it's a closed path, sometimes it isn't... Sigh... Still not sure what this accomplishes for us. Bobby On Fri, 30 Jan 2009 04:45:17 -0600, Jens-Peer Kuska <kuska at informatik.uni-leipzig.de> wrote: > Hi, > > and more over, it does it wrong because I try your example with > > data = Table[ > RandomReal[{.8, 1.2}] {Cos[t], Sin[t]}, {t, 0, 2 \[Pi] - 2 \[Pi]/6, > 2 \[Pi]/32}]; > > got the data > data-{{0.899074, 0}, {0.931267, 0.185241}, {1.10439, 0.457454}, > {0.955484, > 0.638434}, {0.795648, 0.795648}, {0.547609, 0.819554}, {0.318697, > 0.769402}, {0.232974, 1.17124}, {0, 1.18407}, {-0.207593, > 1.04364}, {-0.459194, 1.10859}, {-0.639312, 0.956798}, {-0.664321, > 0.664321}, {-0.953214, 0.636917}, {-0.966874, 0.400492}, {-0.893422, > 0.177713}, {-1.02206, > 0}, {-1.09618, -0.218044}, {-0.995037, -0.412158}, {-0.775199, \ > -0.517972}, {-0.722555, -0.722555}, {-0.643561, -0.963157}, \ > {-0.373253, -0.901112}, {-0.232702, -1.16987}, {0, -0.93512}, \ > {0.189465, -0.952506}, {0.338656, -0.817588}}; > > and the result is > > ListCurvePathPlot[data, InterpolationOrder -> 3, Axes -> False, > InterpolationOrder -> 16] > > not curved, not interpolated and broken into *two* pieces. > > May be you don't understand the function because it is buggy and useless > ... > > Regards > Jens > > David Park wrote: >> I don't understand the new ListCurvePathPlot, which the Help page says: >> "attempts to reconstruct smooth curves defined by the specified set of >> points." >> >> >> >> This plot routine also has the option: InterpolationOrder. And the word >> "Curve" appears not only in the name but repeatedly in the descriptions. >> But look at the following example: >> >> >> >> data = Table[ >> >> RandomReal[{.8, 1.2}] {Cos[t], Sin[t]}, {t, 0, 2 \[Pi] - 2 \[Pi]/6, >> >> 2 \[Pi]/6}]; >> >> ListCurvePathPlot[data, >> >> InterpolationOrder -> 3, >> >> Axes -> False] >> >> >> >> I don't see anything "smooth" or "curvy" about the results! So it seems >> that these terms are a misdirection in understanding the use of the >> routine. >> It appears that what the routine actually does is reorder the points to >> give >> some simpler line (not curve) than the original set of points. But what >> is >> the criterion for this? Is this some well know computational geometry >> algorithm? Was InterpolationOrder included as an option by mistake? Did >> the >> implementation change from the original intention? What is the purpose >> of >> the routine? What is the relation of this and the spline functions? >> >> >> >> David Park >> >> djmpark at comcast.net >> >> <http://home.comcast.net/~djmpark> http://home.comcast.net/~djmpark/ >> > -- DrMajorBob at longhorns.com

**References**:**Re: ListCurvePathPlot***From:*Jens-Peer Kuska <kuska@informatik.uni-leipzig.de>

**Re: Book mathematica 6**

**Re: Re: Re: Simplifying and Rearranging**

**Re: ListCurvePathPlot**

**Re: Re: ListCurvePathPlot**