Re: matrix equation
- To: mathgroup at smc.vnet.net
- Subject: [mg101506] Re: matrix equation
- From: dh <dh at metrohm.com>
- Date: Thu, 9 Jul 2009 01:54:06 -0400 (EDT)
- References: <h2fe6u$ptv$1@smc.vnet.net>
Hi Haibo,
here is a simpler example that shows the essentials.
Daniel
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f[t_] := {{t , t^2}, {t^2, 3 t}};
eq = {f[t] == a[t] .f'[t], a[0] == {{0, 0}, {0, 0}}};
y = a /. NDSolve[eq, a, {t, 0, 0.5}][[1]];
Plot[y[t], {t, 0, .5}]
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Haibo Min wrote:
> Hi, everyone.
> Suppose T is a inversible matrix, and its elements are functions of t.
> Consequently, we may denote this matrix as T[t], and its first and second
> derivative is denoted as T'[t] and T''[t].
> I want to solve a equation as follows:
> (A+B)T+T'==(a+b)T+2T', (A+B)T'+aBT==aT'+(ab+b)T+T'';
> where a,b are known constants, and A,B is what I want to get.
> How to express it in matrix form and solve it?
> Thanks in advance.
>
>