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Re: Inverse / Laplace Transform Halved

  • To: mathgroup at smc.vnet.net
  • Subject: [mg100796] Re: Inverse / Laplace Transform Halved
  • From: Francesco <b.gatessucks at gmail.com>
  • Date: Sun, 14 Jun 2009 05:40:06 -0400 (EDT)
  • References: <h0vtes$6vc$1@smc.vnet.net>

In[5]:= InverseLaplaceTransform[
   LaplaceTransform[BesselI[1, t], t, s, Assumptions -> {s > 1}], s,
   t]

Out[5]= -DiracDelta[t] + 1/2 (BesselI[1, t] + 2 DiracDelta[t])


In[6]:= $Version
Out[6]= "7.0 for Linux x86 (64-bit) (February 18, 2009)"

-Francesco


On 06/13/2009 11:02 AM, Sid wrote:
> Dear MathGroup,
>
> I am currently using Version 6 and have found that
>
> InverseLaplaceTransform[LaplaceTransform[BesselI[1,t],t,s],s,t]
>
> yields, after tidying up, 1/2  BesselI[1,t].
>
>
> Also,
>
> LaplaceTransform[InverseLaplaceTransform[s*Exp[(-a)*Sqrt[s]], s, t],
> t,s]
>
> gives   ((1/2)*s)/E^(a*Sqrt[s]) .
>
>
> Do members have the same problem with Version 7 ?
>
> Is it I who am missing something  here ?
>
>
> Thanks for your help.
>
> Cheers
>
> Sid
>



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