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Re: from the list select

  • To: mathgroup at smc.vnet.net
  • Subject: [mg101085] Re: [mg101048] from the list select
  • From: Leonid Shifrin <lshifr at gmail.com>
  • Date: Tue, 23 Jun 2009 07:08:39 -0400 (EDT)
  • References: <200906220823.EAA09375@smc.vnet.net>

Hi,

namedata = {{"Aardsma", "David", "P"},{"Bay", "Jason", "OF"}}

Solutions:

Cases[namedata, {_, _, "P"}]

Select[namedata, #[[3]] === "P" &]

Next time consider reading the documentation first before posting your
question - this one is simple enough to be figured out even by a complete
novice.

Regards,
Leonid


On Mon, Jun 22, 2009 at 1:23 AM, terrie riley <triley4 at san.rr.com> wrote:

> from this list select the person who has P in the third position
>
>
> namedata = {{"Aardsma", "David", "P"},{"Bay", "Jason", "OF"}}
>
>


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