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Re: from the list select


Brute force:

   where = First@Flatten@Position[Part[#, 3] & /@ namedata, "P"];
   namedata[[where]]

Pattern-matching:

   Cases[namedata, {_,_,"P"}]

terrie riley wrote:
> from this list select the person who has P in the third position
> 
> 
> namedata = {{"Aardsma", "David", "P"},{"Bay", "Jason", "OF"}}
> 

-- 
Murray Eisenberg                     murray at math.umass.edu
Mathematics & Statistics Dept.
Lederle Graduate Research Tower      phone 413 549-1020 (H)
University of Massachusetts                413 545-2859 (W)
710 North Pleasant Street            fax   413 545-1801
Amherst, MA 01003-9305


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