Re: Putting an If in my function

*To*: mathgroup at smc.vnet.net*Subject*: [mg101055] Re: [mg101039] Putting an If in my function*From*: Bob Hanlon <hanlonr at cox.net>*Date*: Tue, 23 Jun 2009 07:02:58 -0400 (EDT)*Reply-to*: hanlonr at cox.net

f[a_, g_, f_, x_, d_, w_] = #5 (1 + ((E^#2 - 1) - (E^#6 - 1))/#3)^(#3*#4) + (#1*((1 + (((E^#2 - 1) - (E^#6 - 1))/#3))^(#3*#4) - 1))/(((E^#2 - 1) - (E^#6 - 1))/#3) &[a, g, f, x, d, w]; f[a_, g_, f_, x_, d_, g_] = Limit[f[a, g, f, x, d, w], w -> g] a f x+d ?? f Bob Hanlon ---- Lobotomy <labbman at gmail.com> wrote: ============= Hi, this is my function #5 (1 + ((E^#2 - 1) - (E^#6 - 1))/#3)^(#3*#4) + (#1*((1 + (((E^#2 - 1) - (E^#6 - 1))/#3))^(#3*#4) - 1))/(((E^#2 - 1) - (E^#6 - 1))/#3) &[a, g, f, x, d, w] in the case when w==g the denominator equals zero. in this case i would like to rewrite the formula above to the much simpler d+a*n. How is this done? I've tried If[w == g, % = d + a*n], but this is not working. Another thing is where to put the "If"