       Re: Putting an If in my function

• To: mathgroup at smc.vnet.net
• Subject: [mg101055] Re: [mg101039] Putting an If in my function
• From: Bob Hanlon <hanlonr at cox.net>
• Date: Tue, 23 Jun 2009 07:02:58 -0400 (EDT)
• Reply-to: hanlonr at cox.net

```f[a_, g_, f_, x_, d_,
w_] = #5 (1 + ((E^#2 - 1) - (E^#6 -
1))/#3)^(#3*#4) + (#1*((1 + (((E^#2 - 1) - (E^#6 -
1))/#3))^(#3*#4) -
1))/(((E^#2 - 1) - (E^#6 - 1))/#3) &[a, g, f, x, d, w];

f[a_, g_, f_, x_, d_, g_] = Limit[f[a, g, f, x, d, w], w -> g]

a f x+d

?? f

Bob Hanlon

---- Lobotomy <labbman at gmail.com> wrote:

=============
Hi, this is my function

#5 (1 + ((E^#2 - 1) - (E^#6 -
1))/#3)^(#3*#4) + (#1*((1 + (((E^#2 - 1) - (E^#6 -
1))/#3))^(#3*#4) -
1))/(((E^#2 - 1) - (E^#6 - 1))/#3) &[a, g, f, x, d, w]

in the case when w==g the denominator equals zero.

in this case i would like to rewrite the formula above to the much
simpler
d+a*n. How is this done? I've tried

If[w == g, % = d + a*n], but this is not working. Another thing is
where to put the "If"

```

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