Conjecture: 2n+1= 2^i+p ; 6k-2 or 6k+2 = 3^i+p
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- Subject: [mg97037] Conjecture: 2n+1= 2^i+p ; 6k-2 or 6k+2 = 3^i+p
- From: Tangerine Luo <tangerine.luo at gmail.com>
- Date: Tue, 3 Mar 2009 05:56:33 -0500 (EST)
I have a conjecture:
Any odd positive number is the sum of 2 to an i-th power and a
2n+1 = 2^i+p
for example: 5 = 2+3 9=4+5 15=2^3+7 905=2^12-3191 ....
as to 2293=2^i +p $B!$(BI don't know i , p . it is sure that i>30 000 if
the conjecture is correct.
n = 3^i+p, (if n=6k-2 or n=6k+2)
for example:8 = 3+5 16=3^2+7 100=3+97, 562 = 3^6 -167
I can't proof this. Do you have any idea?
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