Re: Don't understand the response

*To*: mathgroup at smc.vnet.net*Subject*: [mg97625] Re: [mg97587] Don't understand the response*From*: DrMajorBob <btreat1 at austin.rr.com>*Date*: Tue, 17 Mar 2009 05:00:03 -0500 (EST)*References*: <17032823.1237030239609.JavaMail.root@m02>*Reply-to*: drmajorbob at bigfoot.com

You didn't see fit to give the value of outB, so I'll first conjure one that duplicates your output: outB = RandomInteger[{1, 5}, {3, 2}]; outB[[1 + 1 ;; 3, 1]] = 0; outB {{2, 3}, {0, 4}, {0, 1}} (1 <= 4) And (outB[[1 + 1 ;; 3, 1]] == ConstantArray[0, {3 - (1 + 1) + 1}]) And True^2 Now to deconstruct that: 1 <= 4 True and also (outB[[1 + 1 ;; 3, 1]] == ConstantArray[0, {3 - (1 + 1) + 1}]) True so In[3308] is equivalent to True And True And True^2 (multiplying three symbols, two of which are the same) You could have entered, instead: True ~And~ True True or (1 <= 4) ~And~(outB[[1 + 1 ;; 3, 1]] == ConstantArray[0, {3 - (1 + 1) + 1}]) True or (1 <= 4) && (outB[[1 + 1 ;; 3, 1]] == ConstantArray[0, {3 - (1 + 1) + 1}]) True Bobby On Mon, 16 Mar 2009 04:24:33 -0500, dglawler <dglawler at comcast.net> wrote: > Don't understand the result below. Can someone gently unpack this for > me? > True^2?? > > > In[3308]:= (1 <= 4) And (outB[[1 + 1 ;; 3, 1]] == > ConstantArray[0, {3 - (1 + 1) + 1}]) > > Out[3308]= And True^2 > > Later.........Dennis > > -- DrMajorBob at bigfoot.com