Re: Don't understand the response
- To: mathgroup at smc.vnet.net
- Subject: [mg97625] Re: [mg97587] Don't understand the response
- From: DrMajorBob <btreat1 at austin.rr.com>
- Date: Tue, 17 Mar 2009 05:00:03 -0500 (EST)
- References: <17032823.1237030239609.JavaMail.root@m02>
- Reply-to: drmajorbob at bigfoot.com
You didn't see fit to give the value of outB, so I'll first conjure one
that duplicates your output:
outB = RandomInteger[{1, 5}, {3, 2}];
outB[[1 + 1 ;; 3, 1]] = 0;
outB
{{2, 3}, {0, 4}, {0, 1}}
(1 <= 4) And (outB[[1 + 1 ;; 3, 1]] ==
ConstantArray[0, {3 - (1 + 1) + 1}])
And True^2
Now to deconstruct that:
1 <= 4
True
and also
(outB[[1 + 1 ;; 3, 1]] == ConstantArray[0, {3 - (1 + 1) + 1}])
True
so In[3308] is equivalent to
True And True
And True^2
(multiplying three symbols, two of which are the same)
You could have entered, instead:
True ~And~ True
True
or
(1 <= 4) ~And~(outB[[1 + 1 ;; 3, 1]] ==
ConstantArray[0, {3 - (1 + 1) + 1}])
True
or
(1 <= 4) && (outB[[1 + 1 ;; 3, 1]] ==
ConstantArray[0, {3 - (1 + 1) + 1}])
True
Bobby
On Mon, 16 Mar 2009 04:24:33 -0500, dglawler <dglawler at comcast.net> wrote:
> Don't understand the result below. Can someone gently unpack this for
> me?
> True^2??
>
>
> In[3308]:= (1 <= 4) And (outB[[1 + 1 ;; 3, 1]] ==
> ConstantArray[0, {3 - (1 + 1) + 1}])
>
> Out[3308]= And True^2
>
> Later.........Dennis
>
>
--
DrMajorBob at bigfoot.com