Re: Bug in LaplaceTransform?

*To*: mathgroup at smc.vnet.net*Subject*: [mg97754] Re: Bug in LaplaceTransform?*From*: "Nasser Abbasi" <nma at 12000.org>*Date*: Fri, 20 Mar 2009 02:42:24 -0500 (EST)*References*: <gpsr23$mf1$1@smc.vnet.net>*Reply-to*: "Nasser Abbasi" <nma at 12000.org>

"Wieland Brendel" <wielandbrendel at gmx.net> wrote in message news:gpsr23$mf1$1 at smc.vnet.net... > Dear reader, > how can it happen that Mathematica throws out -i for the Laplace > transform of one, > > LaplaceTransform[1, t, I] = -i? > > After all the Laplace transformation (with s = I) is defined as > > Integrate[Exp[-I t], {t, 0, Infinity}] > > and should be undefined. Am I wrong or is this a bug? > > Thanks for an answer! > Wieland > Laplace transform of 1 is 1/s, right? So, if you used 'I' instead of 's', you get 1/I, right? But 1/I = -I So I think there is no bug here. --Nasser