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Re: Inverse function
*To*: mathgroup at smc.vnet.net
*Subject*: [mg99378] Re: Inverse function
*From*: dh <dh at metrohm.com>
*Date*: Mon, 4 May 2009 06:01:13 -0400 (EDT)
*References*: <gth5gc$evb$1@smc.vnet.net>
Hi,
InverseFunction is only a symbolic inverse. To get the inverse of a
function you may use e.g. Solve or in more complicated cases Reduce.
Your example:
sol=Solve[y == 5/(2 - x), x]
You may write this as a function by e.g.:
fun = Evaluate[x /. sol[[1]] /. y -> #] &
with this:
f[1] evaluates to -3
Daniel
davef wrote:
> I have two questions:
>
> 1. Is it possible to find the inveses function for one-to-one function in Mathematica 7?
>
> For example the inverse of 5/(2-x) is 2-(5/x). I have tried Inverse and InverseFunction but I cannot produce the inverse function.
>
> Can anyone explain how to get Mathematica to produce this result? (See attached output screenshot.)
>
>
> 2. Is it possible to change the format of the output for a recprical?
>
> For example, instead of writing the output of Inverse[5/(2-x)] as (5/(2-x))^-1, can the output be set to produce (2-x)/5?
>
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