Re: Inverse function

*To*: mathgroup at smc.vnet.net*Subject*: [mg99378] Re: Inverse function*From*: dh <dh at metrohm.com>*Date*: Mon, 4 May 2009 06:01:13 -0400 (EDT)*References*: <gth5gc$evb$1@smc.vnet.net>

Hi, InverseFunction is only a symbolic inverse. To get the inverse of a function you may use e.g. Solve or in more complicated cases Reduce. Your example: sol=Solve[y == 5/(2 - x), x] You may write this as a function by e.g.: fun = Evaluate[x /. sol[[1]] /. y -> #] & with this: f[1] evaluates to -3 Daniel davef wrote: > I have two questions: > > 1. Is it possible to find the inveses function for one-to-one function in Mathematica 7? > > For example the inverse of 5/(2-x) is 2-(5/x). I have tried Inverse and InverseFunction but I cannot produce the inverse function. > > Can anyone explain how to get Mathematica to produce this result? (See attached output screenshot.) > > > 2. Is it possible to change the format of the output for a recprical? > > For example, instead of writing the output of Inverse[5/(2-x)] as (5/(2-x))^-1, can the output be set to produce (2-x)/5? >