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Re: Factor and/or Rules replacements
*To*: mathgroup at smc.vnet.net
*Subject*: [mg104492] Re: Factor and/or Rules replacements
*From*: Peter <insomnia.berlin at gmail.com>
*Date*: Sun, 1 Nov 2009 17:56:03 -0500 (EST)
*References*: <hcjjbj$js5$1@smc.vnet.net>
On 1 Nov., 10:11, yves <yves.daup... at solvay.com> wrote:
> Hello everybody,
>
> Here is the model problem:
> I tried to obtain the factorisation of x^2+b x +c and expected to get something like (x-1/2(-b+Sqrt[b^2-4 c))((x-1/2(-b-Sqrt[b^2-4 c)).
>
> So I tried
> in:Factor[x^2+b x + c] and get
> out: c + b x + x^2
> So my first question what should I have done?
>
> I tried another way
> in:sol=Solve[x^2+b x + c == 0,{x}]; and get the couple of replacement rules.
> Next I defined
> in: f=(x-x1)(x-x2)
> and finally I replaced x1 and x2 in succession by
> in:f /. {(sol[[1]] /. x -> x1), (sol[[2]] /. x -> x2)}
> which gave the expected factorisation but enclosed in {}.
> My second question is :
> Is there a simpler way or more compact to replace x1 and x2?
>
> With anticipated thanks.
> Yves
Hi Yves,
you could try:
In[1]:= Times@@(x-x0/.Solve[x0^2+b x0+c==0,x0])
Out[1]= (1/2 (b-Sqrt[b^2-4 c])+x) (1/2 (b+Sqrt[b^2-4 c])+x)
In[2]:= Expand@%
Out[2]= c+b x+x^2
in this moment I do not see any simpler approach.
Peter
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