Re: Re: Mathematica skill level snippet(s)
- To: mathgroup at smc.vnet.net
- Subject: [mg104805] Re: [mg104745] Re: Mathematica skill level snippet(s)
- From: "Nasser M. Abbasi" <nma at 12000.org>
- Date: Tue, 10 Nov 2009 06:01:41 -0500 (EST)
- References: <200911917250.789293@jfultz2winlap>
- Reply-to: "Nasser M. Abbasi" <nma at 12000.org>
From: "John Fultz" <jfultz at wolfram.com> "Stephen Wolfram wrote a blog post which included a ListPlot of the function count from Mathematica's inception to version 7. http://blog.wolfram.com/2008/11/18/surprise-mathematica-70-released-today/ The plot is about a third of the way through the post. Note the number here is significantly below your number because you're counting all System` symbols, whereas he was counting System` *functions*. " Yes, I know about this blog (it is one of the references already on my page), and I actually remember spending sometime trying to find how did Dr Wolfram would have counted the number of functions, but I could not figure it out (the command used to generate the plot was not shown in the blog.) Do you know how to find how many of the Symbols are actually Functions such as Sin,Cos etc.. vs. say function options or other type of symbols? Since the Head of a Function is a Symbol itself I can't just look at the Head of each symbol to find out? In[6]:= Head[Sin] Out[6]= Symbol In[7]:= Head[Joined] Out[7]= Symbol If I filter by attribute, which I think may be the way to do it, then which set of attributes to use? Listable? gives only 264 Length[Select[Names["System`*"], MemberQ[Attributes[#1], Listable] & ]] 264 So, need more attributes which all apply to functions, then get a unique list out, then count it? But I do not know what all the attributes should be. If you know _please_ let me know, and I will add this information to the table. thanks --Nasser