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Re: Re: Non-Linear pendulum
*To*: mathgroup at smc.vnet.net
*Subject*: [mg105011] Re: Re: [mg104874] Non-Linear pendulum
*From*: Alexei Boulbitch <Alexei.Boulbitch at iee.lu>
*Date*: Tue, 17 Nov 2009 05:17:25 -0500 (EST)
Dear David,
in your answer to this question (as well as in some other answers) I met the construction:
\[Theta][t_] = \[Theta][t] /. s
Previously I met constructions like \[Theta][t_] with SetDelayed, rather than with Set. Could you please
comment a bit on the use of such a construct with Set?
Thank you in advance and best regards, Alexei
pendulum = {Line[{{0, 0}, {0, -1}}], Circle[{0, -1.3}, 0.3]};
l = 20;
g = 9.81;
Clear[\[Theta]];
s = First@
NDSolve[{\[Theta]''[t] == -g/l Sin[\[Theta][t]], \[Theta][0] ==
Pi/2, \[Theta]'[0] == 0}, \[Theta], {t, 0, 30}]
\[Theta][t_] = \[Theta][t] /. S
Animate[
Graphics[Rotate[pendulum, \[Theta][t], {0, 0}],
PlotRange -> {{-2, 2}, {-2, .5}}],
{t, 0, 30},
AnimationRunning -> False]
David Park
djmpark at comcast.net
http://home.comcast.net/~djmpark/ <http://home.comcast.net/%7Edjmpark/>
From: Allamarein [mailto:matteo.diplomacy at gmail.com]
I'm getting to know Mathematica. I want to compile a code to see the
non-linear pendulum behavior.
pendulum= {Line[{{0, 0}, {0, -1}}], Circle[{0, -1.3}, 0.3]};
l = 20;
g = 9.81;
s = NDSolve[
{ \[Theta]''[t] == -g /l Sin[\[Theta][t]],
\[Theta][0] == Pi/2,
\[Theta]'[0] == 0}, \[Theta],
{t, 0, 30}];
Animate[
Graphics[Rotate[pendulum, \[Theta[]t], {0, 0}],
PlotRange -> {{-2, 2}, {0, -2}}],
{t, 0, 30}, AnimationRunning -> False]
This code doesn't work. I realized my error is in Rotate argument. If
I change this line with:
Graphics[Rotate[pendulum, Sin[t], {0, 0}]
code runs, but it's not the result (obviously).
How can I correct my code, to see the pendulum oscillates with \[Theta]
[t] law?
--
Alexei Boulbitch, Dr., habil.
Senior Scientist
IEE S.A.
ZAE Weiergewan
11, rue Edmond Reuter
L-5326 Contern
Luxembourg
Phone: +352 2454 2566
Fax: +352 2454 3566
Website: www.iee.lu
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