Re: Bug in Plot3D?

• To: mathgroup at smc.vnet.net
• Subject: [mg105225] Re: Bug in Plot3D?
• From: Bill Rowe <readnews at sbcglobal.net>
• Date: Wed, 25 Nov 2009 02:30:33 -0500 (EST)

```On 11/24/09 at 5:51 AM, wellsoberlin at gmail.com (SixWingedSeraph) wrote:

>The two plot commands in the notebook below should give identical
>outputs, but they don't.  The notebook is posted at
>http://abstractmath.org/MM/MmaBugQ.nb

>a := 9; b := 18;

There is no reason I can see to use SetDelayed here.

>ff[x_, y_, z_] := x + y + z

>gg[x_, y_, z_] := 2*x - 2*y - z

>f[x_, y_] := z /. Solve[ff[x, y, z] == a, z]

Given you are plotting this function, you definitely should be
using Set ("=") instead of SetDelayed (":="). By using
SetDelayed you are telling Mathematica to solve for z every time
Plot supplies a new set of x, y points. This causes Mathematica
to do more work than necessary to create the plot.

>f[x, y]

>g[x_, y_] := z /. Solve[gg[x, y, z] == b, z]

>g[x, y]

>Plot3D[{-x - y + 9, 2*(x - y - 9)}, {x, 6, 10}, {y, -5, 1}...

>Plot3D[{f[x, y], g[x, y]}, {x, 6, 10}, {y, -5, 1}...

You are not plotting the same thing in both cases. That is:

In[14]:= {f[x, y], g[x, y]}

Out[14]= {{-x - y + 9}, {2 (x - y - 9)}}

which is not the same as

{-x - y + 9, 2 (x - y - 9)}

You can make things the same by redefining ff and gg to take the
first solution returned by Solve or by taking the first solution
when plotting

```

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