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Re: How to make {f,g}[a,b,c] to become

  • To: mathgroup at smc.vnet.net
  • Subject: [mg105326] Re: [mg105301] How to make {f,g}[a,b,c] to become
  • From: Bob Hanlon <hanlonr at cox.net>
  • Date: Sat, 28 Nov 2009 01:05:59 -0500 (EST)
  • Reply-to: hanlonr at cox.net

A few more ways of obtaining the table

properties = {"Name", "GDP", "Population"};

Outer[CountryData[#1, #2] &,
  CountryData[], properties] ==
 ({CountryData[#, "Name"],
     CountryData[#, "GDP"],
     CountryData[#, "Population"]} & /@
   CountryData[]) ==
 Quiet[Thread[
     CountryData[#, properties]] & /@
   CountryData[]] ==
 (Table[CountryData[#, p], {p, properties}] & /@
      CountryData[]) ==
 Table[CountryData[c, p],
  {c, CountryData[]}, {p, properties}]

True


Bob Hanlon

---- Bob Hanlon <hanlonr at cox.net> wrote: 

=============

Outer[#2[#1] &, {a, b, c}, {f, g}]

{{f[a], g[a]}, {f[b], g[b]}, {f[c], g[c]}}

Outer[CountryData[#1, #2] &, CountryData[],
  {"Name", "GDP", 
   "Population"}] ==
 ({CountryData[#, "Name"], 
     CountryData[#, "GDP"],
     CountryData[#, "Population"]} & /@ CountryData[])

True


Bob Hanlon

---- Lawrence Teo <lawrenceteo at yahoo.com> wrote: 

=============
I have a question. How to make {f,g}[a,b,c] to become {{f[a],g[a]},{f
[b],g[b]},{f[c],g[c]}}?

I want to do {GPD, Population} for all countries.

Something similar to the following...
{CountryData[#, "GDP"] &, CountryData[#, "Population"] &} /@
 CountryData[]

It ends up in the form of {f,g}[a,b,c,d,...]. I need a way to
'distribute' the country name into the GDP and Population portion.

Thanks.



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