|
[Date Index]
[Thread Index]
[Author Index]
Re: (1234*(2/3)^(Log[1234]/Log[3])) === (1234^(Log[2]/Log[3])) should be?
- To: mathgroup at smc.vnet.net
- Subject: [mg104115] Re: (1234*(2/3)^(Log[1234]/Log[3])) === (1234^(Log[2]/Log[3])) should be?
- From: Andrzej Kozlowski <akoz at mimuw.edu.pl>
- Date: Mon, 19 Oct 2009 08:17:45 -0400 (EDT)
- References: <200910191111.HAA02099@smc.vnet.net>
On 19 Oct 2009, at 20:11, Luka Rahne wrote:
> what should be result of this evaluation?
>
> (1234*(2/3)^(Log[1234]/Log[3])) === (1234^(Log[2]/Log[3]))
>
> subqestion.
>
> How to make this work?
>
(1234*(2/3)^(Log[1234]/Log[3])) == (1234^(Log[2]/Log[3])) // Simplify
True
Andrzej Kozlowski
Prev by Date:
Re: Code folding and wrapping using the input->code method?
Next by Date:
Re: (1234*(2/3)^(Log[1234]/Log[3])) === (1234^(Log[2]/Log[3])) should be?
Previous by thread:
(1234*(2/3)^(Log[1234]/Log[3])) === (1234^(Log[2]/Log[3])) should be?
Next by thread:
Re: (1234*(2/3)^(Log[1234]/Log[3])) === (1234^(Log[2]/Log[3])) should be?
|