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Re: ReplaceAll and rules from a list v7.0

  • To: mathgroup at smc.vnet.net
  • Subject: [mg104264] Re: ReplaceAll and rules from a list v7.0
  • From: Bill Rowe <readnews at sbcglobal.net>
  • Date: Sun, 25 Oct 2009 01:08:39 -0400 (EDT)

On 10/24/09 at 2:40 AM, kristophs.post at web.de (kristoph) wrote:

>Suppose I have the equation

>x=a+b

>and the list

>l={{1,1},{2,2},{3,3}}

>How can I quickly assign the list to the above equation, that is, I
>would like to get the following result

>{2,4,6}

>The first element of each sub-list should be assigned to a and the
>second to b.

In[6]:= x = a + b;
l = {{1, 1}, {2, 2}, {3, 3}};
x /. Thread[{a, b} -> #] & /@ l

Out[8]= {2,4,6}




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