Re: Ill-conditioned linear system
- To: mathgroup at smc.vnet.net
- Subject: [mg104344] Re: Ill-conditioned linear system
- From: Roman <rschmied at gmail.com>
- Date: Wed, 28 Oct 2009 04:08:41 -0500 (EST)
- References: <hc6gl0$5r2$1@smc.vnet.net>
Hi, I would simply re-formulate your problem MatrixExp[M] . C . x = b into C . x = MatrixExp[-M] . b which, as you say, is well-conditioned: x = LinearSolve[C, MatrixExp[-M].b] Roman.