Multiply 2 matrices where one contains differential operators with one that contains functions of x and y

*To*: mathgroup at smc.vnet.net*Subject*: [mg104417] Multiply 2 matrices where one contains differential operators with one that contains functions of x and y*From*: "Nasser M. Abbasi" <nma at 12000.org>*Date*: Sat, 31 Oct 2009 01:50:39 -0500 (EST)*References*: <20091029225146.K51SM.569239.imail@eastrmwml30>*Reply-to*: "Nasser M. Abbasi" <nma at 12000.org>

Hello, Version 7 Lets say A is a 3 by 2 matrix, which contains differential operators in some entries and 0 in all other entries, as in A= { { d/dx , 0 } , {0 , d/dy } , { d/dy , d/dx } } And I want to multiply the above with say a 2 by 3 matrix whose entries are functions of x and y as in B = {{x*y, x^3*y, 3*x + y^2}, {2*x, x^4*y, y^2}} I'd like to somehow be able to do A.B, but ofcourse here I can't, as I need to "apply" the operator on each function as the matrix multiplication is being carried out. I tried to somehow integrate applying the operators in A into the matrix multiplication of A by B, but could not find a short "functional" way. So I ended up solving this by doing the matrix multiplication by hand using for loops (oh no) so that I can 'get inside' the loop and be able to apply the operator to each entry. This is my solution: A = {{D[#1, x] & , 0 & }, {0 & , D[#1, y] & }, {D[#1, y] & , D[#1, x] & }} B = {{x*y, x^3*y, 3*x + y^2}, {2*x, x^4*y, y^2}} {rowsA, colsA} = Dimensions[A]; {rowsB, colsB} = Dimensions[B]; r = Table[0, {rowsA}, {colsB}]; (*where the result of A.B goes *) For[i = 1, i <= rowsA, i++, For[j = 1, j <= colsB, j++, For[ii = 1, ii <= rowsB, ii++, r[[i,j]] = r[[i,j]] + A[[i,ii]] /@ {B[[ii,j]]} ] ] ] MatrixForm[r] The above work, but I am sure a Mathematica expert here can come up with a true functional solution or by using some other Mathematica function which I overlooked to do the above in a more elegent way. --Nasser