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Re: Root again


Am 11.04.2010 10:31, schrieb Maxim:
...

> Peter
>
> I don't know how to do it without using this small trick, but it's
> possible to solve such problems symbolically:
>
> In[1]:= Reduce[
>   Root[1 + t # + #^6&, 2]<  0 || Root[1 + t # + #^6&, 2]>= 0, t]
>
> Out[1]= t<= Root[-46656 + 3125 #1^6&, 1] || t>= Root[-46656 + 3125
> #1^6&, 2]
>
> Maxim Rytin
> m.r at inbox.ru
>

Thank you Maxim,
this is really simple ;-)

but it does not give a hint what "NumericalFunction" is. Maybe someone 
of the Mathematica team could give an answer?


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