Services & Resources / Wolfram Forums / MathGroup Archive
-----

MathGroup Archive 2010

[Date Index] [Thread Index] [Author Index]

Search the Archive

Re: 3D interpolating

  • To: mathgroup at smc.vnet.net
  • Subject: [mg109153] Re: 3D interpolating
  • From: "Hans Michel" <hmichel at cox.net>
  • Date: Wed, 14 Apr 2010 05:15:30 -0400 (EDT)
  • References: <hq0mlv$jsb$1@smc.vnet.net>

Try
data = {{{0, 0}, 0}, {{1, 1}, 1}, {{2, 2}, 2}};
f = ListInterpolation[data[[All, 1]], InterpolationOrder -> 1]

You may need use Sort or SortBy on data if column 2 is not well ordered

Because your sample does not have enough points without 
 InterpolationOrder ->1 you would order too high warning. See: 
ref/message/ListInterpolation/inhr

Hans

"michuco" <ibmichuco at hotmail.com> wrote in message 
news:hq0mlv$jsb$1 at smc.vnet.net...
> Hi all,
>
> I am trying to fit a series of 3D points, say
>
> data = {{{0, 0}, 0}, {{1, 1}, 1}, {{2, 2}, 2}};
>
> with
>
> f = Interpolation[data]
>
> which gives me the error
>
> Interpolation::indim: The coordinates do not lie on a structured \
> tensor product grid.
>
> I think that I got the data format wrong, but I can't tell from the
> Help library of Mathematica 6.
>
> Ideas? Thanks in advance,
>
> Michuco
> 



  • Prev by Date: Re: Formatting GraphicsRow/column
  • Next by Date: Re: How to dynamically build a list of rules
  • Previous by thread: Re: 3D interpolating
  • Next by thread: Re: 3D interpolating