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Re: All componens different

  • To: mathgroup at
  • Subject: [mg111999] Re: All componens different
  • From: "Harvey P. Dale" <hpd1 at>
  • Date: Tue, 24 Aug 2010 06:12:46 -0400 (EDT)




-----Original Message-----
From: Dr. Wolfgang Hintze [mailto:weh at]
Sent: Monday, August 23, 2010 2:52 AM
To: mathgroup at
Subject: [mg111999] [mg111996] All componens different

Given a list v of natural numbers I'm looking for a function d[v_] that
returns True if all components are different and False otherwise.

One solution is

d1[v_] :== ! Or @@ Flatten[Table[v[[i]] ==== v[[k]], {i, 1, Length[v]},
{k, i + 1, Length[v]}]]

Can you find more efficient (and elegant) solutions?


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