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Re: Replacement Rule with Sqrt in denominator

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  • Subject: [mg114324] Re: Replacement Rule with Sqrt in denominator
  • From: Murray Eisenberg <murray at>
  • Date: Wed, 1 Dec 2010 02:10:45 -0500 (EST)

It's not a bug (and not really a "feature", either):


Thus there is no "Sqrt[x] really in 1/Sqrt[x] (the latter being just a 
quick input form), just as there is no "I" in 1+2I.

On 11/30/2010 4:05 AM, Richard Fateman wrote:
> On 11/20/2010 3:11 AM, kj wrote:
>> I don't know a way to write the replacement rule so that it works
>> for both Sqrt[x] and 1/Sqrt[x], but maybe someone else does.
>> ~kj
> See
> which describes how one can automatically produce rules that overcome
> this bug in Mathematica.  oops.  I mean rules that overcome this
> "feature" in Mathematica.

Murray Eisenberg                     murray at
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