[Date Index]
[Thread Index]
[Author Index]
Re: Question about Solve and Reduce (mathematica 8)
*To*: mathgroup at smc.vnet.net
*Subject*: [mg114530] Re: Question about Solve and Reduce (mathematica 8)
*From*: Andrzej Kozlowski <akoz at mimuw.edu.pl>
*Date*: Tue, 7 Dec 2010 06:44:14 -0500 (EST)
On 6 Dec 2010, at 03:53, olfa wrote:
> Hi Mathematica Community,
>
> 1)now that Solve can handle inequalities in Mathematica 8, what is the
> main difference between Solve and Reduce in finding solutions for a
> given variable(s)?
> 2)is it possible to let Solve give solutions not in terms of rules of
> the form x->sol but as it is displayed by Reduce?
>
> Thank you very much.
>
There are a number of differences. For example, Solve will return {{}} when the set of solutions is full dimensional:
Solve[Sqrt[x+1]<1-Sqrt[3x^3+1],x,Reals]
During evaluation of In[423]:== Solve::fulldim: The solution set contains a full-dimensional component; use Reduce for complete solution information.
>>
{{}}
while Reduce will give you the complete solution
Reduce[Sqrt[x+1]<1-Sqrt[3x^3+1],x,Reals]
Root[3 #1^3+1&,1]<==x<Root[9 #1^6-6 #1^4-6 #1^3+#1^2-2 #1-3&,1]
Also, Solve only finds generic solutions, so:
Solve[a^2 x^2>==a^2 (x^2+1),x,Reals]
{}
while
Reduce[a^2 x^2>==a^2 (x^2+1),x,Reals]
a====0
There are other differences too. On the whole Solve has the advantage in speed, Reduce in the completeness of the solutions it returns.
Andrzej Kozlowski
Prev by Date:
**Re: FileName Widget**
Next by Date:
**Re: Counting number of numbers in a large list between two valus**
Previous by thread:
**Question about Solve and Reduce (mathematica 8)**
Next by thread:
**Re: How to get coefficient list from a**
| |