       Re: what's wrong with this?!!

• To: mathgroup at smc.vnet.net
• Subject: [mg114936] Re: what's wrong with this?!!
• From: olfa mraihi <olfa.mraihi at yahoo.fr>
• Date: Thu, 23 Dec 2010 03:54:34 -0500 (EST)

So what's wrong with Reduce in Mathematica 5 to get the output Element[n
| iP, Integers] && n<= iP < 1 + n?

knowing that Reduce has not been modified in Mathematica 8 so why does it give the correct output which is Element[n | iP, Integers] && iP == n?

I 'm using Mathematica 5 and I'm constrained to use it because some of my examples work on Mathematica 5 but not on Mathematica 8.

Thank you.

--- En date de : Mer 22.12.10, Andrzej Kozlowski <akoz at mimuw.edu.pl> a =
=E9crit :

De: Andrzej Kozlowski <akoz at mimuw.edu.pl>
Objet: Re: [mg114909] what's wrong with this?!!
=C0: "olfa" <olfa.mraihi at yahoo.fr>
Cc: mathgroup at smc.vnet.net
Date: Mercredi 22 d=E9cembre 2010, 9h48

The output I get (with Mathematica 8) is:

In:= Reduce[Element[{iP, n}, Integers] &&  !iP < n &&
Exists[{iPP}, iPP < n && iP == iPP + 1], {iP},
Backsubstitution -> True]

Element[n | iP, Integers] && iP == n

Andrzej Kozlowski

On 22 Dec 2010, at 08:36, olfa wrote:

> Hi mathematica community,
>
> this is the system to solve:
> Reduce[
> Element[{iP, N}, Integers] &&
> Not[(iP < N)] &&
> Exists[{iPP}, (iPP < N) && iP == iPP + 1],
> {iP}, Backsubstitution -> True]
>
> the output is:
> (N | iP) =E2=88=88 Integers && N =E2=89=A4 iP < 1 + N
>
> but it should be:
> iP==N
>
> so what's the problem what is missing to get the correct output?
>
> thank you very much.

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