Re: Mathematica 6.01 does not know one can not divide by

• To: mathgroup at smc.vnet.net
• Subject: [mg107213] Re: [mg107140] Mathematica 6.01 does not know one can not divide by
• From: Tomas Garza <tgarza10 at msn.com>
• Date: Fri, 5 Feb 2010 03:25:46 -0500 (EST)
• References: <201002041124.GAA29654@smc.vnet.net>

```Does it, really?

In[98]:= NSolve[3*x+(1/(x-5))==15+(1/(x-5)),x]

Out[98]= {{x->5.}}

In[99]:= 3*x+(1/(x-5))==15+(1/(x-5))/.{x->5.`}

During evaluation of In[99]:= Power::infy: Infinite expression 1/0. encountered. >>
During evaluation of In[99]:= Power::infy: Infinite expression 1/0. encountered. >>

Out[99]= ComplexInfinity==ComplexInfinity

Tomas

> Date: Thu, 4 Feb 2010 06:24:12 -0500
> From: zeno333 at mindspring.com
> Subject: [mg107140] Mathematica 6.01 does not know one can not divide by 0??
> To: mathgroup at smc.vnet.net
>
> I had Mathematica 6.01 try and solve this " equation", and it gives an
> answer back of 5, which if substituted back into the equation, one
> would be dividing by 0. Code and result here...
>
> NSolve[3*x + (1/(x - 5)) == 15 + (1/(x - 5)), x]
> {{x -> 5.}}
>

```

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