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Re: Radicals simplify
*To*: mathgroup at smc.vnet.net
*Subject*: [mg106439] Re: Radicals simplify
*From*: dh <dh at metrohm.com>
*Date*: Tue, 12 Jan 2010 05:16:35 -0500 (EST)
*References*: <hic37h$5ef$1@smc.vnet.net> <201001111030.FAA23508@smc.vnet.net> <higdmv$kir$1@smc.vnet.net>
Hi Murray,
stright from the manual:
"With the default setting ComplexityFunction->Automatic, forms are
ranked primarily according to their LeafCount, with corrections to treat
integers with more digits as more complex."
Daniel
Murray Eisenberg wrote:
> Mathematica 7 documentation does NOT say that LeafCount is the criterion
> for determining simplicity, that is, the default value of
> ComplexityFunction. Rather it says:
>
> "The default ComplexityFunction counts the subexpressions and digits
> of integers."
>
> But it does not even say how it combines the counts of the number of
> subexpressions and digits of integers!
>
> On 1/11/2010 5:30 AM, dh wrote:
>> Hi,
>>
>> why do you think x(x^2 y^3)^(1/4) is simpler than (x^6 y^3)^(1/4)?
>>
>> Mathematica needs some criterion for this decision. The default criterion is the
>>
>> "LeafCount[..]". If that does not suit you, you must define another
>>
>> criterion.
>>
>> Daniel
>>
>>
>>
>> francix wrote:
>>
>>> Hi,
>>> I am using Matematica 7 and need some help with Radicals.
>>> If I do
>>> Simplify[(x^4 y^3)^(1/4), x>= 0] I correctly have
>>> x (y^3)^(1/4)
>>> But If I do
>>> Simplify[(x^6 y^3)^(1/4), x>= 0] I get
>>> (x^6 y^3)^(1/4) and not the correct answer x(x^2 y^3)^(1/4)
>>> Thanks in advanced.
>>
>>
>
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