       • To: mathgroup at smc.vnet.net
• Subject: [mg106439] Re: Radicals simplify
• From: dh <dh at metrohm.com>
• Date: Tue, 12 Jan 2010 05:16:35 -0500 (EST)
• References: <hic37h\$5ef\$1@smc.vnet.net> <201001111030.FAA23508@smc.vnet.net> <higdmv\$kir\$1@smc.vnet.net>

```
Hi Murray,

stright from the manual:

"With the default setting ComplexityFunction->Automatic, forms are

ranked primarily according to their LeafCount, with corrections to treat

integers with more digits as more complex."

Daniel

Murray Eisenberg wrote:

> Mathematica 7 documentation does NOT say that LeafCount is the criterion

> for determining simplicity, that is, the default value of

> ComplexityFunction.  Rather it says:

>

>    "The default ComplexityFunction counts the subexpressions and digits

> of integers."

>

> But it does not even say how it combines the counts of the number of

> subexpressions and digits of integers!

>

> On 1/11/2010 5:30 AM, dh wrote:

>> Hi,

>>

>> why do you think x(x^2 y^3)^(1/4) is simpler than (x^6 y^3)^(1/4)?

>>

>> Mathematica needs some criterion for this decision. The default criterion is the

>>

>> "LeafCount[..]". If that does not suit you, you must define another

>>

>> criterion.

>>

>> Daniel

>>

>>

>>

>> francix wrote:

>>

>>> Hi,

>>> I am using Matematica 7 and need some help with Radicals.

>>> If I do

>>> Simplify[(x^4 y^3)^(1/4), x>= 0] I correctly have

>>> x (y^3)^(1/4)

>>> But If I do

>>> Simplify[(x^6 y^3)^(1/4), x>= 0] I get

>>> (x^6 y^3)^(1/4) and not the correct answer  x(x^2 y^3)^(1/4)

>>> Thanks in advanced.

>>

>>

>

```

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