Re: Re: AstronomicalData - solar ecliptic longitude

*To*: mathgroup at smc.vnet.net*Subject*: [mg106605] Re: [mg106597] Re: AstronomicalData - solar ecliptic longitude*From*: Canopus56 <canopus56 at yahoo.com>*Date*: Mon, 18 Jan 2010 02:34:55 -0500 (EST)*References*: <his6t3$l4q$1@smc.vnet.net> <201001171230.HAA10068@smc.vnet.net>

Thanks, magma, That's close. RA-Dec to ecliptic is not that tough. - Kurt ----- Original Message ---- From: magma <maderri2 at gmail.com> To: mathgroup at smc.vnet.net Sent: Sun, January 17, 2010 5:30:37 AM Subject: [mg106605] [mg106597] Re: AstronomicalData - solar ecliptic longitude On Jan 16, 12:11 pm, Canopus56 <canopu... at yahoo.com> wrote: > Mathematica 7 contains a new powerful astronomical feature - AstronomicalData. It appears to intended to partially supercede the outdated 1997 = _Scientific Astronomer_ package. Is there a way by hour to tease out th= e current ecliptic longitude of the Sun from this function? > Thanks, Kurt Directly from AstronomicalData does not seem so. You can get the RA and Decl of the Sun and then convert it to ecliptic long, if you know the formula. For example: AstronomicalData["Sun", {"RightAscension", {2010, 3, 21}}] AstronomicalData["Sun", {"Declination", {2010, 3, 21}}] give you the RA and Decl of the Sun next 21st March. As we can see we are very close to the first point of Aries >From this info you can get the ecliptic lat/long using the formulas d= escribed in the wikipedia page below: http://en.wikipedia.org/wiki/Ecl= iptic_coordinate_system hth

**References**:**Re: AstronomicalData - solar ecliptic longitude***From:*magma <maderri2@gmail.com>