Mathematica 9 is now available
Services & Resources / Wolfram Forums / MathGroup Archive
-----

MathGroup Archive 2010

[Date Index] [Thread Index] [Author Index]

Search the Archive

Re: Contour integral around z_infinity != negative around origin

  • To: mathgroup at smc.vnet.net
  • Subject: [mg106616] Re: Contour integral around z_infinity != negative around origin
  • From: dh <dh at metrohm.com>
  • Date: Mon, 18 Jan 2010 05:39:50 -0500 (EST)
  • References: <hiuuq0$90e$1@smc.vnet.net>


Hi Vince,

the question is if there are poles somewhere (inlcusive infinity, 

assuming there are no essential singularities). If not the intergral is 

always zero and the sign does not matter.

Maybe you remember the transformation x->1/x that changes the 

orientation of the contour and thereby the sign.

Daniel



Vince Virgilio wrote:

> If I recall grad school correctly, the contour integral of f around

> z_infinity is not simply the negative of the contour integral of f

> around the origin. I never understood why not. I don't think I could

> pose the question to Mathematica properly, anytime soon. So I thought

> I'd bring it to this list. Would someone formulate these two contour

> integrals as Mathematica expressions, and attempt to draw an equality

> between the two? I'd be curious to see how Mathematica takes it.

> 

> If this is nonsense, just leave it in wonderland.

> 

> Thanks,

> 

> Vince Virgilio

> 




  • Prev by Date: Re: Re: Simplify with NestedLessLess?
  • Next by Date: Re: Convert string list to number list
  • Previous by thread: was Re: More /.{I->-1} craziness. Schools are conservative. So are
  • Next by thread: Re: Trouble with coupled quadratic equations where the solutions are