Re: Replace list element based on a condition how to
- To: mathgroup at smc.vnet.net
- Subject: [mg106666] Re: [mg106630] Replace list element based on a condition how to
- From: Bob Hanlon <hanlonr at cox.net>
- Date: Wed, 20 Jan 2010 06:50:59 -0500 (EST)
- Reply-to: hanlonr at cox.net
lst1 = {18, 19, 20, 21, 22, 23, 0, 1, 2, 3};
fncHourFix[h_] := If[(h - 6) < 0, h - 6 + 24, h - 6];
lst2 = lst1 /. h_?NumericQ -> fncHourFix[h]
{12,13,14,15,16,17,18,19,20,21}
lst2 = fncHourFix /@ lst1
{12,13,14,15,16,17,18,19,20,21}
lst2 = Mod[lst1 + 18, 24]
{12,13,14,15,16,17,18,19,20,21}
Bob Hanlon
---- Canopus56 <canopus56 at yahoo.com> wrote:
=============
Q1. Is there a way to replace a list based on a condition?
I have a list of integers -
lst1 = {18, 19, 20, 21, 22, 23, 0, 1, 2, 3}
that I would like to replace with the following rule -
fncHourFix[h_] := If[(h - 6) < 0, h - 6 + 24, h - 6];
but the replace function -
lst2 = lst1 /. {i_} :> fncHourFix[{i}]
- bombs out.
I've tried several variants.
Any pointers would be appreciated.
Thanks - Kurt