Re: Frame

• To: mathgroup at smc.vnet.net
• Subject: [mg106911] Re: Frame
• From: David Bailey <dave at removedbailey.co.uk>
• Date: Wed, 27 Jan 2010 06:25:10 -0500 (EST)
• References: <hjonel\$4ln\$1@smc.vnet.net>

```John wrote:
> Mathematica 6, windows XP
>
> Style[Binomial[n, j] == (n!/(j! (n - j)!) // HoldForm),
>   FontFamily -> "Tahoma", FontSize -> 24, Bold] // TraditionalForm
>
> The above typesets the combinatorial symbol perfectly. Is there a way
> to put a frame around the printed symbol? Attempts to put it in a grid
> failed.
>
> John
>
It isn't clear where you want to put the frame - maybe one of these does
what you want:

Framed[Style[Binomial[n, j] == (n!/(j! (n - j)!) // HoldForm),
FontFamily -> "Tahoma", FontSize -> 24, Bold]] // TraditionalForm

Style[Framed[Binomial[n, j]] == (n!/(j! (n - j)!) // HoldForm),
FontFamily -> "Tahoma", FontSize -> 24, Bold] // TraditionalForm

Style[Binomial[n, j] == (n!/(j! (n - j)!) // HoldForm),
FontFamily -> "Tahoma", FontSize -> 24, Bold] /.
a_ == b_ -> Grid[{{a, b}}, Frame -> All] // TraditionalForm

More generally, you will find you get far more help here if you post
some actual non-working code. Someone will almost certainly fix it for
you, and explain what you were doing wrong.

From your description, I can't even tell what items you want to put in
a grid, but obviously you can put anything you like in a grid if you use
the right syntax :) One way might be to start with a trivial grid and
then replace the items with whatever you need, extending the 2D array as
required:

Grid[{{a, b, c}, {d, e, f}}, Frame -> All]

If in doubt, the trick in Mathematica, is to start with something
trivial or supplied in the help system, and progressively modify it to
whatever you want.

David Bailey
http://www.dbaileyconsultancy.co.uk

```

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