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Re: plot

I'm not certain of your question. Why don't you just do something like this:

Plot[((2 x + 1) Sqrt[x + 1])/Sqrt[x - 1], {x, 1, 5},
 PlotRange -> {Full, {5, 20}},
 Frame -> True] 

David Park
djmpark at  

From: agua [mailto:auguaylupo at] 

With  Plot[( (2x+1) Sqrt[x+1] ) / Sqrt[x-1] ,{x,-5,5}]
hoped to obtain a graph only for x>1.

What happened?

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