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Re: plot

  • To: mathgroup at smc.vnet.net
  • Subject: [mg110707] Re: plot
  • From: "David Park" <djmpark at comcast.net>
  • Date: Sat, 3 Jul 2010 08:16:03 -0400 (EDT)

I'm not certain of your question. Why don't you just do something like this:

Plot[((2 x + 1) Sqrt[x + 1])/Sqrt[x - 1], {x, 1, 5},
 PlotRange -> {Full, {5, 20}},
 Frame -> True] 


David Park
djmpark at comcast.net
http://home.comcast.net/~djmpark/  



From: agua [mailto:auguaylupo at gmail.com] 


Hi
With  Plot[( (2x+1) Sqrt[x+1] ) / Sqrt[x-1] ,{x,-5,5}]
hoped to obtain a graph only for x>1.

What happened?
regards.




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