Re: Kolmogorov-Smirnov 2-sample test
- To: mathgroup at smc.vnet.net
- Subject: [mg111284] Re: Kolmogorov-Smirnov 2-sample test
- From: Ray Koopman <koopman at sfu.ca>
- Date: Mon, 26 Jul 2010 06:37:47 -0400 (EDT)
ks2a[y1_,y2_] := Block[{n1 = Length@y1, n2 = Length@y2,
pool = Sort@Join[y1,y2], x,n,u}, If[Equal@@pool, {0,1.}, {x =
Max@Abs[n2*Tr@UnitStep[y1-#]-n1*Tr@UnitStep[y2-#]&/@Rest@Union@pool],
n = n1+n2; u = Table[0,{n2+1}]; Do[ Which[
i+j == 0, u[[j+1]] = 1,
i+j < n && pool[[i+j]] < pool[[i+j+1]] && Abs[n2*i-n1*j] >= x,
u[[j+1]] = 0,
i == 0, u[[j+1]] = u[[j]],
j > 0, u[[j+1]] += u[[j]]], {i,0,n1},{j,0,n2}];
N[1 - Last@u/Multinomial[n1,n2]]}] ]
ks2a[{1,1,1},{1,1,1,1}]
{0,1.}
----- Aaron Bramson <aaronbramson at gmail.com> wrote:
> Hello everybody and thank you,
>
> This has been very helpful, and now the two-sided K-S test for Mathematica
> is online for everybody to enjoy.
>
> I have implemented the new code from Andy and from Ray on my data set and
> the code from Ray works out better for me...though I don't have the skill to
> decipher what that "ugly" code is doing, I've verified several results so
> I'm using those exact p-values. I'm going to build a table of the p-values
> from these tests (which is made into plot over time with the test being
> performed on the individual-trial data streams of two cohorts at each time
> step).
>
> I have one last question, or maybe it's a request.. In Ray's code if I put
> in two data sets wherein all the points are at the same value (e.g. all
> zero) the result is not a K-stat of 0, and a p-value of 1, but rather
> {-\[Infinity], 0.}. That doesn't seem like the right answer (and in any
> case not the answer that I expect or can use) so this input combination
> doesn't work with how the technique calculates the stats. So I'd like to
> request a small change to the code Ray provided so that if the inputs are
> all identical the output is {0,1} instead of {-\[Infinity], 0.}. I could do
> this post-facto with a replacement rule, but it would probably be better and
> faster to do this in the original calculation. But with THAT code I don't
> know where to make the appropriate changes.
>
> Again, thanks everybody for your help.
>
> Best,
> Aaron
>
> p.s. I may end up using the Kuiper test and I might therefore have a similar
> question about implementing that in Mathematica very soon.