Re: Colored wire ContourPlot3d
- To: mathgroup at smc.vnet.net
- Subject: [mg110097] Re: Colored wire ContourPlot3d
- From: Patrick Scheibe <pscheibe at trm.uni-leipzig.de>
- Date: Tue, 1 Jun 2010 07:41:14 -0400 (EDT)
Hi,
for your first question there's a fast answer: Use None instead
of smth with Opacity
ContourPlot3D[f[x, y, z], {x, -5, 5}, {y, -5, 5}, {z, -5, 5},
Contours -> {-0.1, 0.1}, PlotRange -> All, ContourStyle -> None,
MeshStyle -> {{Red, Opacity[0.1]}, {Blue, Opacity[0.1]}}]
is incredible fast compared to your version.
For your second question, right now I don't see a faster way than you
suggested.
For your third question I would suggest that you check out the
MaxRecursion option. To let Mathematica subdivide regions with
complex structures is very often better than just increase the plot-
points.
Plot[Sin[x^2], {x, 0, 2 Pi}, PlotPoints -> 5, MaxRecursion -> #,
Mesh -> All] & /@ {3, 10}
Cheers
Patrick
Am Jun 1, 2010 um 10:23 AM schrieb michuco:
> Hi,
>
> I am having problem converting something that I used
> to be able to do in earlier versions of Mathematica (<6.0).
>
> I would like to plot a wired-only 3d plot of a function,
> say
>
> f[x_,y_,z] := (x - 0.5) Exp[-0.5 ({x, y, z} - {0.5, 1., 1.}).
> ({x, y, z} - {0.5, 1., 1.})];
>
> At the moment, when I want the equivalue contourplot
> of this function at {-0.1,01} value, I use
>
> ContourPlot3D[f[x, y, z], {x, -5, 5}, {y, -5, 5}, {z, -5, 5},
> Contours -> {-0.1, 0.1}, PlotRange -> All,
> ContourStyle -> {Opacity[0.]},
> MeshStyle -> {{Red, Opacity[0.1]}, {Blue, Opacity[0.1]}}]
>
>
> There are two problems with this. Firstly, the rotation is
> much slower than I imagined it would be. I think that the
> option ContourStyle -> {Opacity[0.]} means that the
> surface is still part of the graphics. Secondly, I couldn't
> get the mesh to be in different colors,.i.e., the negative
> contour in blue and the positive in red, or one in dotted
> mesh, the other in continuous mesh.
>
> Right now, I plot the negative and positive parts separately
> then combine them with Show. There must be a more
> elegant way to do this. (In earlier versions, I used Shading
> = False).
>
> Finally, a general problem that I have with ContourPlot3D.
> Sometimes, parts of the isovalue surface is missing. I
> assume that they fall between the grid points because
> I usually get rid of them by increasing PlotPoints, this
> is both time consuming and tedious. Is there a better
> option?
>
> Many thanks in advance,
>
> Michuco
>