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Re: Simplifying complicated expressions
*To*: mathgroup at smc.vnet.net
*Subject*: [mg110193] Re: Simplifying complicated expressions
*From*: Bob Hanlon <hanlonr at cox.net>
*Date*: Mon, 7 Jun 2010 08:07:17 -0400 (EDT)
Make the LHS of the rule as simple as possible
expr = Total[(x^2 + y^3 - x^2 y^2 + Sqrt[z3 + y2])^Range[-2, 2]];
While straight replacement isn't very effective
expr /. (x^2 + y^3 - x^2 y^2 + Sqrt[z3 + y2]) -> f1xyz
f1xyz + (-(x^2*y^2) + x^2 + y^3 + Sqrt[y2 + z3])^2 +
1/(-(x^2*y^2) + x^2 + y^3 + Sqrt[y2 + z3]) +
1/(-(x^2*y^2) + x^2 + y^3 + Sqrt[y2 + z3])^2 + 1
Using a simple LHS pattern that doesn't change in the various components of the FullForm representation works well
repl = Sqrt[z3 + y2] -> f1xyz - (x^2 + y^3 - x^2 y^2);
expr2 = expr /. repl
f1xyz^2+1/f1xyz^2+f1xyz+1/f1xyz+1
val = {x -> 3, y -> 1, y2 -> 6, z3 -> 10};
repl2 = Solve[Equal @@ repl, f1xyz][[1]] /. val
{f1xyz->5}
expr2 /. repl2
781/25
% == (expr /. val)
True
Bob Hanlon
---- "S. B. Gray" <stevebg at ROADRUNNER.COM> wrote:
=============
Suppose I have a long complex expression in which terms like
(x^2+y^3-x^2y^2+Sqrt[z3+y2]) (for a simple example) appear many times
along with various powers and the reciprocals of it, etc. To make the
expression comprehensible and to make the computation faster, I would
like to substitute say "f1xyz" for it everywhere it appears. The normal
/. and -> substitutions and patterns are not adequate for this. Of
course at evaluation time I want to compute f1xyz only once and not have
the final formula revert to the original variables. How do I prevent that?
Also a welcome addition to Mathematica would be the ability to find these
repeated expressions automatically and put them in, because doing it
manually is very error-prone and slow.
Tips will be appreciated!
Steve Gray
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