       Re: Find value of unknown const that causes integral to equal some value

• To: mathgroup at smc.vnet.net
• Subject: [mg110334] Re: Find value of unknown const that causes integral to equal some value
• From: Bill Rowe <readnews at sbcglobal.net>
• Date: Sun, 13 Jun 2010 04:13:19 -0400 (EDT)

```On 6/12/10 at 5:30 AM, jason.lee.quinn at gmail.com (Jason Quinn) wrote:

>Suppose I have an expression of the form

>1/2 = int_0^1 besselI[0,x*t] dt

>and I want to find the value of "x" that will make the integral
>true. Can Mathematica handle such situations? I've tried all the
>main suspects that I get warnings that the expression depends on x
>in a non- algebraic way. The numerical tasks do not seem to work
>either. The expression above is just a made-up example, but in
>general, what do to when you are trying to solve equations of this
>type?  I could certainly write a function that find the value
>iteratively myself, but I'd be surprised if such a thing doesn't

For a numeric solution to non-algebraic expressions try
FindRoot. However, for your specific example, there doesn't
appear to be any solution. That is:

In:= int = Integrate[BesselI[0, x t], {t, 0, 1}]

Out= HypergeometricPFQ[{1/2}, {1, 3/2}, x^2/4]

In:= FindMinimum[int, x]

Out= {1.,{x->-7.63245*10^-12}}

And note for solving equations with an integral in them, it is
almost always better to first solve the integral then solve for
the solution. This ensures the integral is not evaluated
repeatedly needlessly.

```

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