MathGroup Archive 2010

[Date Index] [Thread Index] [Author Index]

Search the Archive

Re: partial derivate of a function of vector variable

  • To: mathgroup at smc.vnet.net
  • Subject: [mg108633] Re: partial derivate of a function of vector variable
  • From: dh <dh at metrohm.com>
  • Date: Thu, 25 Mar 2010 06:08:24 -0500 (EST)
  • References: <hofa0t$4fd$1@smc.vnet.net>

Hi,
f[x_]:=..
is a function of one argument (even if your scalar is a list) and not a 
function of several variables. Therefore there are no partial derivatives.
The easiest soultion would be to define a function of several variables, 
but you do not want to do this.
Another solution is to "create" a function of several variables on the 
fly, e.g. using dummy variables like:
D[f[{x1,x2},x1]]/.{x1->first argument, x2->second argument}
or we may use a pure function like:
Derivative[1, 0][Evaluate@f[{#1, #2}] &]
or another simpler possibility:
Evaluate@D[f[{#1, #2}], #1]&

Daniel

On 25.03.2010 10:22, atlas shrugger wrote:
> Hi,
>
> Let's say have function f of vector variable x.
> f[x_] := x[[1]]^2 + x[[2]]^2
>
> How to compute partial derivate by x_1?
> Something like D[f[x], {{x[[1]]}}] does not work.
>
> I don't want to rewrite function f as f[x1_,x2_].
>
> Thanks for help.
>


-- 

Daniel Huber
Metrohm Ltd.
Oberdorfstr. 68
CH-9100 Herisau
Tel. +41 71 353 8585, Fax +41 71 353 8907
E-Mail:<mailto:dh at metrohm.com>
Internet:<http://www.metrohm.com>



  • Prev by Date: Re: counting number of variables in an expression
  • Next by Date: Re: Fourier transform of exponential function
  • Previous by thread: Re: partial derivate of a function of vector variable
  • Next by thread: Re: partial derivate of a function of vector variable