Re: Fourier transform of exponential function
- To: mathgroup at smc.vnet.net
- Subject: [mg108716] Re: Fourier transform of exponential function
- From: dh <dh at metrohm.com>
- Date: Mon, 29 Mar 2010 05:21:01 -0500 (EST)
- References: <hofg7f$f89$1@smc.vnet.net> <hofhko$g30$1@smc.vnet.net> <hoklh5$shr$1@smc.vnet.net>
Hi,
the Fourier transform for an interval (-Infinity.Infinity) is defined
as: Limit[1/L Integral[...,{x,-L,L}],L->Infinity]
The factor 1/L produces the convergence for Cos[t], Exp[I t] etc. But
not for Exp[t].
Daniel
On 27.03.2010 11:09, ALittleDog wrote:
> Following the previous question, may it be said that a periodic has
> its Fourier transform and a non-periodic function has its Fourier
> transformed iff it is square integrable.
>
--
Daniel Huber
Metrohm Ltd.
Oberdorfstr. 68
CH-9100 Herisau
Tel. +41 71 353 8585, Fax +41 71 353 8907
E-Mail:<mailto:dh at metrohm.com>
Internet:<http://www.metrohm.com>