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Re: innerApply[{f, g}, {{a, b}, {c, d}}] = {f[a, b], g[c, d]} ?

  • To: mathgroup at smc.vnet.net
  • Subject: [mg109743] Re: innerApply[{f, g}, {{a, b}, {c, d}}] = {f[a, b], g[c, d]} ?
  • From: Ray Koopman <koopman at sfu.ca>
  • Date: Fri, 14 May 2010 05:36:41 -0400 (EDT)
  • References: <hsgnjt$d6o$1@smc.vnet.net>

On May 13, 4:25 am, Fred Klingener <gigabitbuc... at BrockEng.com> wrote:
> This seems to work fine, but there must be a less clumsy way to do it:
>
> Clear[innerApply, functionList, argumentList, f, g, a, b, c, d]
>
> innerApply[functionList_, argumentList_] :=
>  Table[functionList[[j]] @@ argumentList[[j]], {j, 1,
>    Length[functionList]}]
>
> In[770]:= innerApply[{f, g}, {{a, b}, {c, d}}]
> Out[770]= {f[a, b], g[c, d]}
>
> TIA,
> Fred Klingener

This will always work:

In[1]:= MapThread[Apply,{{f,g},{{a,b},{c,d}}}]

Out[1]= {f[a,b],g[c,d]}

This will work only if the sublists in the second list
have different lengths:

In[2]:= Inner[Apply,{f,g},{{a,b},{c,d,e}},List]

Out[2]= {f[a,b],g[c,d,e]}


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