Re: How can I generate this graphic?
- To: mathgroup at smc.vnet.net
- Subject: [mg113585] Re: How can I generate this graphic?
- From: Vicent <vginer at gmail.com>
- Date: Wed, 3 Nov 2010 02:56:50 -0500 (EST)
- References: <AANLkTi=tL4NB8=ObF1623NAFxuaekj415C5d2yC=u-aa@mail.gmail.com>
Hello again.
I've found a solution to the question I reported previously, using
"ListContourPlot" function:
DataFor Plotting = Table[myfunc[x, y], {x, 1, 20, 1}, {y, 1, 20, 1}]
ListContourPlot[DataForPlotting, InterpolationOrder -> 0, ContourLabels ->
All, PerformanceGoal -> "Quality"]
I get this:
http://dl.dropbox.com/u/155485/discrete_contour_plot_with_mathematica.png
As you can see, I don't get any contour labels. Moreover, I would like to
know if the purple "square" that is located on the surface defined by the
set [1 , 2] x [2 , 3] corresponds to the pair (x=1 , y=2) or (x=2 , y=3),
for example.
So, given this solution, I still would need your advice regarding how to
"tune" this graphic.
Thank you very much in advance!!
--
Vicent
On Tue, Nov 2, 2010 at 14:30, Vicent <vginer at gmail.com> wrote:
> Hello to all.
>
> I want to make you a question about how to plot a specific graphic with
> Mathematica 7.0.
>
> I have a function "myfunc" defined on two discrete variables, say x and
> y. And I want to represent graphically "myfunc".
>
> I can generate some graphics with ListPlot3D and ListContourPlot
> that are close to what I want, but in both cases there is an interpolation,
> which is OK but it is not necessary, and I would like to be able to generate
> a graphic (2D or 3D) without any interpolation.
>
> More precisely, I would like to generate a 2D graphic, the X and Y axis
> representing the discrete variables x and y, respectively, with a
> "point" (or "big square") for each integer combination of (x, y), the color
> of the point being related with the value of myfunc(x,y) . I mean, the
> greater the value of myfunc(x,y) is, the lighter (or whatever) the color
> of the associated point is. It would be like a kind of "ListContourPlot",
> but without interpolating.
>
> I have data arranged in this way:
>
> DataForPlotting = Table[myfunc[x, y], {x, 1, 20, 1}, {y, 1, 20, 1}]
>
>
> but of course I could do it in another way if necessary.
>
> This is an image of what I want to achieve:
> http://dl.dropbox.com/u/155485/discrete_contour_plot.png . In case you
> can't access it, please let me know it.
>
> I think it can be possible to build a graphic similar to that one with
> Mathematica, but I am not sure of the easiest (or more logical or more
> practical) way to do it, as I am just a beginner.
>
> So, I would appreciate your help in this point.
>
> Thank you very much in advance for your help!
>
> --
> Vicent Giner-Bosch
>
