MathGroup Archive 2010

[Date Index] [Thread Index] [Author Index]

Search the Archive

Replacement Rule with Sqrt in denominator

  • To: mathgroup at smc.vnet.net
  • Subject: [mg113967] Replacement Rule with Sqrt in denominator
  • From: Themis Matsoukas <tmatsoukas at me.com>
  • Date: Fri, 19 Nov 2010 05:11:34 -0500 (EST)

This replacement rule works,

Sqrt[-4 \[Zeta]^2 + (1 + \[Rho]^2)^2] /. 
 Sqrt[-4 \[Zeta]^2 + (1 + \[Rho]^2)^2] -> G

G

but this doesn't:

1/Sqrt[-4 \[Zeta]^2 + (1 + \[Rho]^2)^2] /. 
 Sqrt[-4 \[Zeta]^2 + (1 + \[Rho]^2)^2] -> G

1/Sqrt[-4 \[Zeta]^2 + (1 + \[Rho]^2)^2]

The only difference is that the quantity to be replaced is in the denominator. If I remove Sqrt from the replacement rule it will work but I don't understand why a square root in the denominator (but not in the numerator) causes the rule to fail. 

Themis


  • Prev by Date: Why does "Normal" not create a list of line graphics primitives from
  • Next by Date: Re: exponential format
  • Previous by thread: Re: Why does "Normal" not create a list of line graphics primitives from
  • Next by thread: Re: Replacement Rule with Sqrt in denominator