Mathematica 9 is now available
Services & Resources / Wolfram Forums / MathGroup Archive
-----

MathGroup Archive 2010

[Date Index] [Thread Index] [Author Index]

Search the Archive

Re: maximum of a series

  • To: mathgroup at smc.vnet.net
  • Subject: [mg114022] Re: maximum of a series
  • From: Bob Hanlon <hanlonr at cox.net>
  • Date: Sat, 20 Nov 2010 18:26:33 -0500 (EST)

m[i_, n_] == HoldForm[Max[Table[Sum[a[k], {k, i, j}], {j, i, n}]]];

m[i, n]

HoldForm[Max[Table[Sum[a[k], {k, i, j}], {j, i, n}]]]

m[3, 5]

HoldForm[Max[Table[Sum[a[k], {k, 3, j}], {j, 3, 5}]]]

% // ReleaseHold

Max[a[3], a[3] + a[4], a[3] + a[4] + a[5]]


Bob Hanlon

---- olfa mraihi <olfa.mraihi at yahoo.fr> wrote:

==========================
Thank you Bob for the reply,
=C2 
I tried to use Table but the problem is that I need to use it symbolically =
(without having values for i and n) which means
Max[Table[Sum[a[k], {k, i, j}], {j, i, n}]]
but unfortunately=C2 I=C2 get this error :Iterator {j,i,n} does not hav=
e appropriate bounds
=C2 
so how to deal with that?
=C2 
Regards,

--- En date de=C2 : Ven 19.11.10, Bob Hanlon <hanlonr at cox.net> a =C3=A9cr=
it=C2 :


De: Bob Hanlon <hanlonr at cox.net>
Objet: Re: [mg113951] maximum of a series
=C3=80: "olfa" <olfa.mraihi at yahoo.fr>, mathgroup at smc.vnet.net
Date: Vendredi 19 novembre 2010, 16h22



m[i_Integer, n_Integer] :==
Max[Table[Sum[a[k], {k, i, j}], {j, i, n}]] /; n >== i

m[3, 5]

Max[a[3], a[3] + a[4], a[3] + a[4] + a[5]]


Bob Hanlon

---- olfa <olfa.mraihi at yahoo.fr> wrote:

==========================
Hi Mathematica Community,

how can I represent for example
the maximum of the summations :sum[a[k],{k,i,j}] where j varies from i
to n?

Thank you






--

Bob Hanlon


  • Prev by Date: Finding a function that makes it possible to Solve[ ] a system of equations
  • Next by Date: Re: exponential format
  • Previous by thread: Re: maximum of a series
  • Next by thread: Re: maximum of a series